441x^2-1=0

Solution for 441x^2-1=0 equation:

441x^2-1=0

a = 441; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·441·(-1)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42}{2*441}=\frac{-42}{882}
=-1/21
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42}{2*441}=\frac{42}{882}
=1/21
$